(Gauss’s Law)
A uniform enclosure for a region would be a sphere. For a sphere, surface area = Assuming the surface enclosing the charge is a sphere,
So,
May 20, 20251 min read
∬AE⋅dA=ε0q (Gauss’s Law)
A uniform enclosure for a region would be a sphere. For a sphere, surface area = 4πr2 Assuming the surface enclosing the charge is a sphere,
∬AE⋅dA=E⋅4πr2
So, E⋅4πr2=ε0q
⟹E=4πr21ε0q
⟹E=4πε01r2q